Please help me to solve this question.

A=266CM

Step-by-step explanation:

p=2l + 2w                                   l=2x+1             w=x+5

66=2[2x+1] + 2{x+5]                  l=2x9 + 1           w=9+5

66=4x+2 + 2x+10                      l=18+1                 w=14

66=6x+12                                   l=19

66-12=6x

54=6x                                      A=L x W

x=9                                         A=19 x 14

                                             A=266CM

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v