magine that you are conducting a one-variable chi-square test to investigate the hypothesis that there are equal numbers of cat lovers and dog lovers in the office at work. Having conducted a survey, you found 150 preferred dogs and 120 preferred cats. What would the expected frequencies be in each cell? 135 150 and 120 270 More information is needed to calculate the expected frequencies.

a. 135 is correct

Step-by-step explanation:

We have the following information:

dogs lover: 150

cats lover: 120

as the null hypothesis:

H, there are equal number of dogs lover and cats lover, so the expected frequency in each cell will be equal and that is:

f = (150 + 120) / 2

f = 270/2 = 135

so option a. 135 is correct

47 - 90 = 43

43 - 180 = x

x = 137

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet