a bag contains a mixture of almonds walnuts and cashews there's an equal quantity of each nut. If a nut is chosen randomly out of the bag what is the probability that an almond will be selected or that a cashew will be selected

P(either almond or cashew) = ⅔

Step-by-step explanation:

We are told that the bag contains a mixture of almonds walnuts and cashews of equal number.

Since the 3 nuts are equal in number, they will have a ratio of 1:1:1.

So, when a nut is chosen randomly,

Probability of choosing almond = 1/3

Probability of choosing cashew = 1/3

Thus,

Probability of choosing either almond or cashew in a random selection will be the sum of their individual probability.

So,

P(either almond or cashew) = ⅓ + ⅓ = ⅔

$15 each

step-by-step explanation:

$45/3 children= $15 each