A six-sided number cube is rolled two times. What is the probability of rolling a 4 both times?

1/36

Explanation: In this problem, we're given that a number cube is rolled twice and we're asked to find the probability of rolling a 4 and a 4.

It's important to understand that the two rolls of the number cube are independent events because the results of one role does not affect the results of the other roll.

To find the probability of two independent events, we first find the probability of each event, then we multiply the probabilities.

So let's first find the probability of rolling

a 4 with our first role of the number cube.

We can find the probability of an event using the following ratio:

number of favorable outcomes over total number of outcomes

Since there's only one way to roll a 4 and there are six possible outcomes 1, 2, 3, 4, 5, and 6, the probability of rolling a 4 is 1/6.

Next, we find the probability of rolling a 4 with our second roll of the number cube, which would also be 1/6.

Now, to find the probability of rolling a 4 and a 4,

we simply multiply the probabilities.

Now multiply 1/6 x 1/6 by multiplying across the top and bottom.

This gives us 1/36.

So the probability or likelihood of rolling a 4 two times in a row is 1/36.  

pls ask

1.true 2.false? ? i think. .

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