Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position with its terminal ray extending through point b, what is the cosine of the angle?

Step-by-step explanation:

Coordinates of Point b

b lies on the circle whose equation is

Comparing with the general form a circle with center at the origin:

The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.

For an angle drawn in standard position through point b,

x=-8 which is negative

y=15 which is positive

Therefore, the angle is in Quadrant II.

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%

i think its a.

hope this