Given the function f(x)= x^2-7 and g(x) = 2x-x^3 what is the value of f(g(2))

9

Step-by-step explanation:

First lets find g(2) because thats inside the f equation.

g(x) = 2x-x^3

g(2) = 2(2) - (2)^3

g(2) = 4 - 8

g(2) = - 4

So now we are finding

f(g(2)) => f(-4)

f(x) = x^2 - 7

f(-4) = (-4)^2 - 7

Remember, because the square is outside the parentheses due to us plugging in a value, it becomes positive

f(-4) = 16 - 7

f(-4) = 9

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step-by-step explanation: