A theater group made appearances in two cities. The hotel charge before tax in the second city was $1500 lower than in the first. The tax in the staty was 10%, and the tax in the second city was 5%. The total hotel tax paid for the two cities was $600. How much was the hotel charge in each oty before tax?

The Hotel charge without tax in first city is $3500 and The hotel charge before tax in the second city is 2000

Step-by-step explanation:

Let x be the hotel charge without tax in first city

We are given that The hotel charge before tax in the second city was $1500 lower than in the first.

So, Hotel  charge without tax in second city =x-1500

Tax% in first city = 10%

So, tax in first city = 0.1x

Tax% in second city =5%

So, tax in second city = 0.05(x-1500)

We are given that The total hotel tax paid for the two cities was $600.

So,0.1x+0.05(x-1500)=600

0.1x+0.05x+75=600

0.15x=600-75

x=3500

Hotel charge without tax in first city = $3500

The hotel charge before tax in the second city =x-1500=3500-1500=2000

Hence The Hotel charge without tax in first city is $3500 and The hotel charge before tax in the second city is 2000

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: