Integral cos(3x)^3sen(3x)^7dx

One way to do this is to exploit the Pythagorean identity,

to rewrite

so that

Then substitute and to get the integral

which is one correct form of the antiderivative. There's no reason we can't use the identity from before to express the integrand in terms of powers of cos(3x) instead.

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

30005

yes ok