Find the area of a circle with the given equation.
(x-7)2+(y + 9)2 =137

 137π

The usual formula for a circle centered at (a,b), with radius r,

(x - a)² + (y - b)² = r²

The area of the circle is πr², so 137π

is only a line? i think so

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length