WHAT IS THE PYTHOGERON TRIPLETS IF ONE NUMBER IS 36

Step-by-step

Let the given number be n>2.

For n even, n2+((n/2)2–1)2=((n/2)2+1)2.

For n odd,  n2+((n2–1)/2)2=((n2+1)/2)2

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standard form of a pythagorean triplet is 2m, m²+1, m²-1

let us take 2m as 36. so

2m=36, m=36/2

therefore m=18

m²+1  =18²+1   = 324+1   =325

m²-1   =18²-1    = 324-1    =323

therefore  36,325,323 form a pythagorean triplet.

For checking, 36²+323² should be equal to 325²

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(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47