Two boys divided $3.36 so that one boy received 12 cents less than three times as much as the other. How was the money divided?

x + y = 3.36 --> the boys are splitting $3.36

x = 3y - .12 --> one boy received $.12 less than 3 times as much as the other

--> substitute the second equation for the x in the first equation

(3y - .12) + y = 3.36 --> combine like terms

4y - .12 = 3.36 --> add .12 to both sides of the equation

4y = 3.48 --> divide both sides by 4

y = .87

the other boy gets $0.87

substitute into x = 3y - 12

x = 3(.87) - .12

x = 2.61 - .12

x = 2.49

the first boy gets $2.49

the answer will be b x² +x-1

step-by-step explanation: