Let (-3,5) be a point on the terminal side of theta. Find the exact values of sin theta, secant theta, and tangent theta Can someone please help me out with this? If possible, providing a diagram would be helpful!

Cosθ = 0.5145

Sinθ = 0.8575

Secθ = 1.9436

tanθ = 1.667

Step-by-step explanation:

From the figure attached,

Point P(-3, 5) is on the terminal side and AB is the initial side of the angle PAB.

If m∠PAB = θ

AB =

     =

     = 5.831

Then Cosθ = =

Cosθ = 0.5145

Sinθ =

Sinθ =

Sinθ = 0.8575

Secθ =

Secθ =

Secθ = 1.944

tanθ =

tanθ =

tanθ = 1.667

answer: 45

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3