Fred needs to write the equation of the line. He used (10,64)and (12.5,73) to find the slope, which is 3.6 The equation off the trend line is A. y=28x+3.6

B. y=3.6x+28

C. y=3.6+100

D. y=100x+3.6

i think this could be a possible answer (1 / 84) -1

good luck! : d

i dony know

step-by-step explanation:

answer: 193

explanation:

200-7 = 193

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west