What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x= -b IVb2 - 400
20
x = 5110/5
N
x= -5110,5
N
0 x = -52/5
o x=575

   x  =  

Step-by-step explanation:

Given equation f(x) = x² + 5 x +5

The roots of the Quadratic equation   ax²+bx+c =0 are

Given equation f(x) = x² + 5 x +5

comparing           ax²+bx+c =0 is

                a = 1 , b = 5 and c = 5

            x  =  

             x  = -7.76 ,  x = -2.76 ,

idk i would have to be there to under stand it

step-by-step explanation:

idk i would have to be there to under stand it

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: