Model 1: X is distributed as Poiss(λ) for some unknown λ>0. Model 2: X takes values in {1,2,3,4,5,6,≥7}, and for i=1,2,…7, we let pi denote the (unknown) probability that X=i. Here "≥7" is a placeholder for when the number of siblings is at least 7. For example, we do not distinguish between an individual having 7 siblings or 10 siblings in this model. Which one of the following best describes an advantage of using a Poisson distribution (Model 1) over the distribution in Model 2 to model X? A. It allows us to model the data continuously.
B. It allows individuals to have an arbitrarily large number of siblings.
C. It reduces the amount of unknowns needed for modeling.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation:

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .