Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi
A. No solution
B. Infinitely many sol...
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Mathematics, 05.06.2020 13:57 Zacwn6360
Solve sin^2 2θ=-1-cos^2θ on the interval 0<θ<2pi
A. No solution
B. Infinitely many solutions
C. 0, 2pi/3, 4pi/3, 2pi
D. 2pi/3, 4pi/3
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