A diameter of a particular circle has endpoints at A(-1, -2) and B(3,10). Which of the following is the slope of the tangent drawn to this circle at point B?

A) -1/2
B) 4/5
C) -1/3
D) -4

Option C) is correct

Step-by-step explanation:

Given: Endpoints of the diameter of the circle are A(-1, -2) and B(3,10)

To find: slope of the tangent drawn to the circle at point B

Solution:

Let

Centre of the circle =

Let

Distance formula states that distance between points (a,b) and (c,d) is given by

Radius of the circle = Distance between points and = units

Let r = units

Equation of a circle is given by

Differentiate with respect to x

Put

So,

slope of the tangent drawn to this circle at point B =

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i