PLEASE HELP, you have to write the equation in y=Mx+b form but you have to also pay attention to the scale of the graph

y = (1/8)x + 23

Explanation:

Given:

The equation of line y = M*x + b

This line pass (0, 23) and (40, 28)

Solve:

23 = M*0 + b

28 = M*40 + b

From 1st equation:

=> b = 23

Subtract 1st equation from 2nd equation:

     5 = M*40

=> M = 5/40 = 1/8

The equation of line:

=> y = (1/8)x + 23

Hope this helps!

:)