Fifteen percent of the students at Central High take Spanish, 12% take French, and 4% take both. If a student is selected at random, what is the probability that the student takes Spanish or French?

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Complete Question

Fifteen percent of the students at Central High take Spanish, 12% take French, and 4% take both. If a student is selected at random, what is the

probability that the student takes Spanish or French?

A 31%

B. 27%

C. 23%

D. 19%

C. 23%

Step-by-step explanation:

At Central High

From the question, we are told that:

Spanish = 15%

French = 12%

Spanish and French = 4%

French or Spanish = unknown

Therefore, the probability that a student at random takes Spanish or French

= P(Spanish) + P(French) - P(Spanish and French)

= 15% + 12% - 4%

= 27% - 4%

= 23%