In a blind taste test, do people prefer pâté or dog food? To investigate, Bohannon et al. (2010) presented 1818 college‑educated adults with unlabeled samples of dog food (Newman's Own Organics Canned Turkey & Chicken) and four meat products meant for humans (duck liver mousse, pork liver pâté, liverwurst, and Spam). Participants were asked to rank their preferences. Two of 1818 participants ranked the dog food first, whereas the other 1616 participants chose one of the other items. Based on these results, can you conclude that people are less likely to prefer dog food over all human food than would be expected by chance? Use the significance level =0.05.level α=0.05. C

The conclusion is that people are less likely to prefer dog food over all human food than would be expected by chance

Step-by-step explanation:

From the question we are told that

   The sample size for first sample is  

     The sample size for second sample  is

     The number that ranked the dog food first

     The number that chose one of the other items is  

The sample proportion for first sample  is  

=>  

=>  

The sample proportion for second sample   is  

The value of the pooled proportion is evaluated as

Test statistics

So since the test  statistics is within the rejection region for the left tailed test

  The null hypothesis is rejected

The conclusion is  that people are less likely to prefer dog food over all human food than would be expected by chance

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

1k

step-by-step explanation:

-6k+7k

(-6+7)k

1k