An equation of an ellipse is given. x2 16 + y2 25 = 1 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = 0,−5 (smaller y-value) vertex (x, y) = 0,5 (larger y-value) focus (x, y) = 0,−3 (smaller y-value) focus (x, y) = 0,3 (larger y-value) eccentricity 3 5 (b) Determine the length of the major axis.

(a)

(b)Length of the major axis=10

Step-by-step explanation:

When the major axis of an ellipse is parallel to the y-axis.The standard form of the equation of an ellipse is given as:

Given the equation:

(I)The coordinates of the vertices are

Therefore, the vertices are at (0,-5) and (0,5).

(II)The coordinates of the foci are

The coordinates of the foci are (0,-3) and (0,3).

(III)Eccentricity

This is the ratio of the distance c between the center of the ellipse and each focus to the length of the semi major axis.

Simply put, Eccentricity =c/a

Eccentricity=3/5

(b)Length of the major axis

The length of the major axis=2a

=2(5)=10.

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: