Find the values of a and b that make f continuous everywhere.
f(x) =
(x2 − 4) / (x − 2) if x < 2
ax2 − bx + 3 if 2 ≤ x < 3
4x − a + b if x ≥ 3
a =
b =

dd

step-by-step explanation:

dd

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐