Which rule describes the composition of transformations that maps pre-image ABCD to final image A"B"C"D"?
Orx-axis 07-61(x, y)
O T-620rx-axis (x, v)
O Rogo T-6, 1(x, y)
OT-610 RO, 900(x,

The composition transformation process is from ABCD to A'B'C'D', then

to A''B''C''D''.

Correct response:

The given coordinates of the pre-image ABCD are;

A(3, 5), B(6, 5), C(4, 1), D(1, 1).

The coordinates of the image D'C'A'B' are;

A'(3, -5), B'(6, -5), C'(4, -1), and D'(1, -1).

Therefore, the rule that gives the coordinates of A'B'C'D' from ABCD

(x, y) (x, -y)

The rule for a reflection across the x-axis is; (x, y) (x, -y)

Therefore;

The rule that gives A'B'C'D', from ABCD is a reflection across the x-axis.

The rule that gives A''B''C''D'' from A'B'C'D' is the a translation 6 units left and 1 unit up, which is;

Therefore composition transformation that maps pre-image ABCD to

final image A''B''C''D'' is given by a reflection followed by a translation,

with the second transformation coming first in the expression as follows;

Learn more about composition transformation here:

link

link

Step-by-step explanation:

We can see in the picture that the first step is transform ABCD to A'B'C'D'. To do this, ABCD is reflected over the x-axis.

Then, A'B'C'D' should be translated -6 units to the right, that is, on the x-axis; and 1 unit up, that is, on the y-axis.

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75