A fortune 500 company concerned about the retirement investments made by its employees collected the following data: age of employee, amount contributed monthly, and type of contribution (401(k), Roth IRA, etc.). Select the choice below that correctly names all the relevant variables and only the relevant variables, correctly identifies them as qualitative or quantitative, and correctly indicates the unit of measure for quantitative variables. A. Age of employee, quantitative, years; amount contributed monthly, quantitative, dollars; type of contribution, qualitative. B. Age of employee, quantitative, years; amount contributed monthly, quantitative, dollars; type of contribution, qualitative; fortune 500 companies, qualitative. C. Age of employee, quantitative, years; amount contributed monthly, quantitative, dollars; type of contribution, quantitative, dollars. D. Age of employee, quantitative, years; amount contributed monthly, categorical; type of contribution, categorical E. Age of employee, quantitative, years; amount contributed monthly, quantitative, dollars.

answer: this is not a question

step-by-step explanation: this is a answer

answer: idk wbu

step-by-step explanation: umm..

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step-by-step explanation:

ever thing time 1 is a multiply by 1 it get  

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.