Determine the attributes of the hyperbola represented by this equation: (y-21)^2/20^2-(x+20)^2/21^2=1

The vertices are A: (-41,21) and (1,21), B: (-20,0) and (-20,42), C: (-20,1) and (-20,41), D: (20,1) and (20,41).
The foci are A; (-50,21) and (10,21), B: (-20,-8) and (-20, 50), C: (-20,-10) and (-20,52), D; (20,-8) and (20,42)

The above answer is correct.

1. C

2. B

Step-by-step explanation: I got this right on Edmentum.

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

hope this is what you were asking for!

step-by-step explanation: