What are the foci of the hyperbola represented by the equation (x^2)/64 - (y^2)/32 =1

x = √2y^2 + 64 or x = √2y^2 + 64

Step-by-step explanation:

Solve for x.

x^2/64 - y^2/32 = 1

Step 1: Add 1/32 y^2 to both sides.

1/64 x^2 + -1/32 y^2 + 1/32 y^2 = 1 + 1/32 y^2

Step 2: Divide both sides by 1/64.

1/64 x^2/ 1/64 = 1/32 y^2 + 1/ 1/64

x^2 = 2y^2 + 64

Step 3:

x = √2y^2 + 64 or x = √2y^2 + 64

answer: 7 x 2/5 = 2.8 hours, is your answer. your welcome! : 3

step-by-step explanation: first work out how long it took to hose 1/7 of the lawn which is 2/5 hours. times that by 7 to get the whole lawn.

sorry i don't know the other answer. i didn't learn what a proportional relationship is.