A student timed his drive to work each day for the three days. The times are shown below. 28 minutes
31 minutes
31 minutes
What was his mean time?
O 28 minutes
29 minutes
https://nsc. edready. org/assessment/retake Topic assessmentid=37063&groupid=2961 4&studyPlanTopicid=41196841& ;continue
30 minutes
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O

The answer is 30 minutes.

Step-by-step explanation:

The average or mean is determined by finding the sum of all of the given values and dividing that by the length of the data set. In this case, three values are given.

By adding 28 + 31 + 31, you get that this is equivalent to 90.

The sum is then divided by the number of values in the data set.

Therefore, 90 minutes / 3 values is equivalent to 30 minutes.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

is should be y = 5x

step-by-step explanation:

correct me if im wrong