Can someone help me I was doing good and then I got stuck on this question what I can’t figure out is how you get the voltage when you only have the watt and resistance . A 60.0 Watt lightbulb has an operating resistance of 220 Ω.

Calculate the operating voltage of this lightbulb.

114.89 V

Step-by-step explanation:

Watts are a measure of power, and there is an equation that relates power, voltage, and resistance. It goes like this:

P=(V^2)/R

Now to find the voltage you want to solve for V

PR = V^2

V =

Now substitute your numbers into the equation and you get your answer

V =

V =

V = 114.89 V

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.  

but there’s no any figure there!