3) The sum and the difference of the LCM and GCD of two numbers are 312 and 264 respectively. Find the numbers if their sum is 168.

The numbers are 72 and 96.

Step-by-step explanation:

LCM + GCF = 312

LCM - GCF = 264

2*LCM = 576

LCM = 576/2 = 288

HCF = 312–288 = 24

The product of two numbers = HCF*LCM

Let the numbers be x and (168-x)

x(168-x) = 24*288 = 6912

x^2–168x+6912 = 0

x = [168 +(168^2 -4*6912)^0.5]/2

= [168 +(28224–27648)^0.5]/2

= [168 + 576^0.5]/2

= (168+24}/2

= 192/2

= 96 and the other number is 168–96 = 72.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

hope this !

let me know