How many quarts of a 50% solution of acid must be added to 20 quarts of a 20% solution of acid to obtain a mixture containing a 40% solution of acid? quarts

Step-by-step explanation:

How many quarts of a 50% solution of acid must be added to 20 quarts of a 20% solution of acid to obtain a mixture containing a 40% solution of acid? quarts

let x = amount of the 50% solution

A typical mixture equation using the decimal equivalent to

0.50x +0 .20(20) =0 .40(x+20)

0.50x + 4 = 0.40x + 8

0.50x - 0.40x = 8 - 4

0.10x = 4

x = 4/0.1

x = 40 qts of 50% solution

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

15 batches are the most you can make

step-by-step explanation: