Carlos' school is selling tickets to a spring musical. On the first day of ticket sales the school sold 6 adult tickets and 12 student tickets for a total of $204. The school took in $79 on the
second day by selling 5 adult tickets and 3 student tickets. What is the price each of one adult
ticket and one student ticket?

Adult ticket = $8

Student ticket = $13

Step-by-step explanation:

Hi, to answer this we have to write a system of equations (sales equations)

6x + 12y =204 (first day)

5x +3y =79 (second day)

Where x is the price of each adult ticket and y is the price of each student ticket.

If we multiply the second equation by 4 , and subtract the first equation to the second equation:

20x +12y =316

-

6x + 12y =204

14x = 112

Solving for x:

x =112/14  

x = 8  

Substituting x=8 on any equation:

5x +3y =79

5(8)+3y =79

40+3y =79

3y =79-40

3y = 39

y =39/3

y = 13

30005

yes ok                                            

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,