Please help? 1: The x-intercepts of a quadratic function are -3 and 5. What is the equation of its axis of symmetry?

#2: The solutions to a quadratic equation are x = 2 or x = -3. What are the x-intercepts of the related quadratic function?

see explanation

Step-by-step explanation:

(1)

The axis of symmetry is situated midway between the x- intercepts, thus

x = = = 1

Equation of axis of symmetry is x = 1 → d

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(2)

The x- intercepts of a quadratic are the solutions, thus

x = 2 and x = - 3 → b

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐