Suppose that there are two types of tickets to a show:Advance and same-day. Advance tickets cost $35 and same day tickets cost $15. For one performance, there were 65 tickets sold in all, and the total amount paid for them was $1475. How many tickets of each type were sold?

   30 $15 tickets and 20 $35 tickets

Step-by-step explanation:

.X%2BY=50

2.15X%2B35Y=1150

From eq. 1,

15X%2B15Y=750

Subtract from eq. 2,

15X%2B35Y-15X-15Y=1150-750

20Y=400

Y=20

Then,

X%2B20=50

X=30

30 $15 tickets and 20 $35 ticket

Hope it helps

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

ur welcome : )