Mathematics, 09.06.2020 20:57 kimmi1489

2x-1=\sqrt{8-x}2x−1=
8−x
what is the extraneous solution

Answers: 1

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2x-1=\sqrt{8-x}2x−1=
8−x
what is the extraneous solution...

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2x-1=\sqrt{8-x}2x−1= 8−x what is the extraneous solution

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Another question on Mathematics

2x-1=\sqrt{8-x}2x−1=
8−x
what is the extraneous solution