The polynomial f(x) is written in factored form: f(x) = (x − 3)(x + 8)(x − 11) What are the zeros of the polynomial function? x = 3, x = 8, x = 11
x = 3, x = −8, x = 11
x = −3, x = 8, x = −11
x = −3, x = 3, x = −8, x = 8, x = −11, x = 11

x=3               x = -8           x = 11

Step-by-step explanation:

f(x) = (x − 3)(x + 8)(x − 11)

Using the zero product property

0 = (x − 3)(x + 8)(x − 11)

0 = x-3      0 = x+8     0 = x-11

x=3               x = -8           x = 11

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i