Assume that the heights of men are normally distributed with a mean of 70.9 inches and a standard deviation of 2.1 inches. If 36 men are randomly selected, find the probability that they have a mean height greater than 71.9 inches. Round to four decimal places.

The probability that they have a mean height greater than 71.9 inches

P(  x⁻ ≥71.9) =  0.0022

Step-by-step explanation:

Explanation:-

Given mean of the Population μ= 70.9

Standard deviation of the Populationσ = 2.1

Given sample size 'n' =36

let x⁻ be the mean height

given  x⁻ =71.9 inches

The probability that they have a mean height greater than 71.9 inches

P(  x⁻ ≥71.9) = P(Z ≥ 2.85)

                    = 1 - P(Z≤ 2.85)

                   =  1 - ( 0.5 + A(2.85)

                   = 0.5 - A( 2.85)

                  = 0.5 - 0.4978

                  = 0.0022

The probability that they have a mean height greater than 71.9 inches

 P(  x⁻ ≥71.9) =  0.0022

i believe the answer is d.

hope it you! : d

22 dimes and 9 nickels

step-by-step explanation: