Anew youth sports center is being built in hadleyville. the perimeter of the rectangular playing field is 536 yards. the length of the field is 22 yards less than quadruple the width. what are the dimensions of the playing field?

W = 58 yards, L = 210 yards

Step-by-step explanation:

P = 2 (L + W)

L = 4w - 22

P = 2 (4W - 22 + W)

536 = 8W - 44 + 2W

536 = 10W - 44

10 W = 536 + 44

10W = 580

W = 58 yards

Since L = 4W - 22

L = 4 (58) - 22

L = 232 - 22

L = 210 yards

1.0

step-by-step explanation:

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.