A parabola is represented by the equation x2 = 4y. What are the coordinates of the focus of the parabola? (0,4) (0,1) (1,0) (4,0

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: