Probability question, which I am stuck on! The probabilities of landing on 1, on 2, on 4, on 5 or on 6 when rolling a biased dice are shown in the table.
*Table In Attachment*

The biased dice is rolled 300 times.
Estimate the total number of times the dice will land on 3 or on 4.

I would like to know what a biased dice is too!

land on 3: 36 times

land on 4: 63 times

Step-by-step explanation:

A biased dice is the opposite of a fair dice.

A fair dice has the same probability of landing any of the six numbers: 1/6

The biased dice has different probabilities for its results.

To solve this question, first we need to find the probability of landing a 3.

The sum of all probabilities need to be 1, so:

0.13 + 0.05 + p(3) + 0.21 + 0.19 + 0.3 = 1

p(3) = 1 - 0.88 = 0.12

If we roll the dice 300 times, the expected number of times the dice will land:

on 3: 300 * p(3) = 300 * 0.12 = 36 times

on 4: 300 * p(4) = 300 * 0.21 = 63 times

99

Step-by-step explanation:

3=0.12

3 =0.12×300=36

4 =0.21×300=63

63+36= 99

lol

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x