15 POINTS!! PLEASE HELP The equation of line WX is 2x + y = −5. What is the equation of a line perpendicular to line WX in slope-intercept form that contains point (−1, −2)?

y = one half x + three halves
y = negative one halfx + three halves
y = one half x − three halves
y = negative one halfx − three halves

y = 1/2x - 1

Step-by-step explanation:

The easiest was you do this is to first rearrange the equation into slope-intercept form (y = mx + b).  After rearranging, you can find the slope (m).

2x + y = -5

y = -2x - 5

The slope is -2.  Since the line we are trying to find is perpendicular, find the inverse and multiply it by -1.

-2  =>  1/2

Now use the point-intercept form to find the new equation.  Use the slope (1/2) and the given point (-1, -2).

y - y₁ = m(x - x₁)

y - (-2) = 1/2(x - (-2))

y + 2 = 1/2(x + 2)

y + 2 = 1/2x + 1

y = 1/2x - 1

The equation of the line perpendicular to line WX is  y = 1/2x - 1.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."