Algebra 2 can anyone help??

Step-by-step explanation:

cot θ=-9.68

cotθ is negative

so θ lies in 2nd or 4th quadrant.

tan θ=-1/9.68

θ=tan ^{-1}(-1/9.68)≈174.1°,354.1°

3.

sec θ=-9.13+5=-8.13

sec θ is negative so θ lies in 2nd or 3rd quadrant.

cos θ=(-1/8.13)

θ=cos^{-1}(-1/8.13)≈97.1°

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24