The function s(t) represents the position of an object at time t moving along a line. Suppose s(2)=69 and s(6)=141.Find the average velocity of the object over the interval of time [2,6 ].

The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.

Step-by-step explanation:

The average velocity can be calculated as the division of the position change by the time change.

Find the average velocity of the object over the interval of time [2,6 ].

6 - 2 = 4 units of time (t, min,...)

s(6) = 141, s(2) = 69

141 - 69 = 72 units of distance(m, km...)

72/4 = 18 u.d./u.t.

The average velocity of the object over the interval of time [2,6] is of 18 units of distance per unit of time.

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)