Consider the tables that represent ordered pairs corresponding to a function and its inverse. When comparing the functions using the values in the table, which conclusion can be made? According to the tables, f(x) does not have a y-intercept. According to the tables, f–1(x) does not have an x-intercept. The domain of f(x) is restricted such that x ≥ 0, so the domain of f–1(x) is restricted such that y ≥ 0. The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.

Step-by-step explanation:

The missing tables are:

First table  

x:    0  1    2

f(x): 1   10  100

Second table

x:         1000   100   10

f^-1(x):  3          2       1  

Option A is not correct because f(x) has a y-intercept at (0, 1)

If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct

Option C is not correct because the domain of f^-1(x) is associated with x values.

Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

41*67/2=1373.5

step-by-step explanation:

i just used a calculator