Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. x4 + x ? 7 = 0, (1, 2)
f(x) = x4 + x ? 7
is (FILL IN)
a) defined
b) continuous
c) negative
d) positive on the closed interval [1, 2],
f(1) = ?? FILL IN , and f(2) = ?? FILL IN
Since ?5 < FILL IN a)? b)? c)? d)0 < 11, there is a number c in (1, 2) such that
f(c) = FILL IN a)? b)? c)0 d)11 e)-5
by the Intermediate Value Theorem. Thus, there is a FILL IN a) limit b)root c) discontinuity of the equation
x4 + x ? 7 = 0
in the interval (1, 2).

The correct option is  d

The correct option is d

The correct option is  c

the correct option is  b

Step-by-step explanation:

The given equation is

The give interval  is

   Now differentiating the equation

Therefore the equation is  positive  at the given interval

       Now at x= 1

       Now at x= 2

Now at  the interval (1,2)

i.e

this tell us that there is a value z within 1,2 and

   f(z) =  0

Which implies that there is a root within (1,2) according to the intermediate value theorem

3, nah jk it's 2

step-by-step explanation:

it is 3 cause i'm sanic

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: