Consider the following data representing the price of laptop computers (in dollars). 12041204, 12061206, 13451345, 13061306, 12071207, 10781078, 13571357, 12321232, 12281228, 13021302, 11891189, 11771177, 10831083, 10941094, 13261326, 10711071, 14271427, 13481348, 14201420, 12531253, 1270 Determine the frequency of the fifth class.

Step-by-step explanation:

The given data is expressed as

1204, 1206, 1345, 1306, 1207, 1078, 1357, 1232, 1228, 1302, 1189, 1177, 1083, 1094, 1326, 1071, 1427, 1348, 1420, 1253, 1270

The number of items in the data, n is 21. The lowest value is 1071 while the highest value is 1427. The convenient starting point would be 1070.5 and the convenient ending point would be 1427.5

The number of class intervals is

√n = √21 = 4.5

Approximately 5

The width of each class interval is

(1427.5 - 1070.5)/5 = 72

The end of each class interval would be

1070.5 + 72 = 1142.5

1142.5 + 72 = 1214.5

1214.5 + 72 = 1286.5

1286.5 + 72 = 1358.5

1358.5 + 72 = 1430.5

The frequency for the fifth class, that is between 1358.5 to 1430.5 would be 2

whatare you sayig

step-by-step explanation:

4a. is 3 miles every hour

4b. is 1/3 of an hour per mile

step-by-step explanation: