If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (StartFraction r Over s EndFraction) (6)? StartFraction 3 (6) minus 1 Over 2 (6) + 1 EndFraction StartFraction (6) Over 2 (6) + 1 EndFraction StartFraction 36 minus 1 Over 26 + 1 EndFraction StartFraction (6) minus 1 Over (6) + 1 EndFraction

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

sweetheart, there isn't a cube below.

median- 36f

mode - none

mean- 33.7 ~ 34f