What would be the approximate 95% confidence interval for the mean number of ounces of catchup bottle in the sample

The 95% confidence interval for the mean number of ounces of ketchup bottle is (23.8, 24.2).

Step-by-step explanation:

The complete question is:

Suppose that a restaurant chain claims that its bottles of ketchup contain 24 ounces of ketchup on average, with a standard deviation of 0.8 ounces. If you took a sample of 49 bottles of ketchup, what would be the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample?

Solution:

The (1 - α)% confidence interval for the population mean is:

The information provided is:

The critical value of z for 95% confidence level is:

*Use a z-table.

Compute the 95% confidence interval for the mean number of ounces of ketchup per bottle as follows:

Thus, the 95% confidence interval for the mean number of ounces of ketchup bottle is (23.8, 24.2).

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

d i think

step-by-step explanation: