Point AAA is at {(-3, 4)}(−3,4)left parenthesis, minus, 3, comma, 4, right parenthesis and point CCC is at {(2,-6)}(2,−6)left parenthesis, 2, comma, minus, 6, right parenthesis. Find the coordinates of point BBB on \overline{AC} AC started overline, A, C, end overline such that the ratio of ABABA, B to ACACA, C is 4:54:54, colon, 5.

The coordinates of point B = (1, -4)

Step-by-step explanation:

Complete Question

Point A is at (−3,4) and point C is at (2,−6). Find the coordinates of point B on line AC such that the ratio of AB to AC is 4:5.

Solution

Point B divides line AC into two parts

A = (-3, 4)

C = (2, -6)

AB:AC = 4:5

If (AB/AC) = (4/5)

5AB = 4AC

But AC = AB + BC

5AB = 4(AB + BC)

5AB = 4AB + 4BC

5AB - 4AB = 4BC

AB = 4BC

(AB/BC) = (4/1)

AB:BC = 4:1

Hence, point B divides line AC internally into two parts with ratio 4:1

Mathematically, if a point P(x, y) divides the coordinates (x₁, y₁) and (x₂, y₂) internally in the ratio m:n then point P(x, y) is given as

x = [(mx₂ + mx₁)/(m + n)]

y = [(my₂ + my₁)/(m + n)]

For this question,

x₂ = 2

x₁ = -3

y₂ = -6

y₁ = 4

m = 4

n = 1

Point B is then described with coordinates

x = [(4×2 + 1×-3)/(4+1)] = (5/5) = 1

y = [(4×-6 + 1×4)/(4+1)] = (-20/5) = -4

Hence, the coordinates of point B is given as

(x, y) = (1, -4)

Hope this Helps!!!

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step-by-step explanation:

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