A missile is launched from the ground. Its height, h(x) can be represented by a qyadratic function in terms of time, x, in seconds after 1 second the missile is 110 feet in the air; after 2 seconds it is 200 feet in the air. Find the height in feet of the missile after 4 seconds in the air

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632

mx+89b(-98)nb

step-by-step explanation:

jbankston is right, use thhe link and you should find the answer.