The perimeter of a rectangle is 280cm. The ratio of the width to the length is 3:4. What is the length of the rectangle?

The length of the rectangle is 80cm and the width is 60cm

The perimeter of the rectangle is given as 280cm and the ratio of the length to width is 3:4.

The formula of perimeter of rectangle is given as;

This implies that

But let's go back to our given ratio

3:4 = l:w

3l = 4w

make w the subject of formula

Let's substitute this into equation (i)

solve for l

Since L = 80, let's substitute it into equation (i)

From the calculations above, we have the following data

The length of the rectangle is 80cm and the width is 60cm

Learn more on perimeter of a rectangle here;

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So first we need to get the perimeter formula. P = 2(w+l). We know P but we dont know w and h.

280/2 = 140. So now we know that 140 = w+l. We also know that the length is 4/3 times greater than the width (we used the ratio). To prove this 3*4/3 = 4, just like in ratio. So we have 2 equations

140 = w+l

l = 4/3w

Now we can plug into 140

140 = w+4/3w

So if you solve algebraicly you get

60 = w.

Now we can find that the length =

80 is the answer to length..

Now to prove answer 60+80 = 140.

So the answer is

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb